12x^2+120x+108=0

Solution for 12x^2+120x+108=0 equation:

12x^2+120x+108=0

a = 12; b = 120; c = +108;
Δ = b2-4ac
Δ = 1202-4·12·108
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-96}{2*12}=\frac{-216}{24}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+96}{2*12}=\frac{-24}{24}
=-1
$